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1890 New Hampshire gubernatorial election

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1890 New Hampshire gubernatorial election

← 1888 November 4, 1890 1892 →
 
Nominee Hiram A. Tuttle Charles H. Amsden
Party Republican Democratic
Popular vote 42,479 42,386
Percentage 49.26% 49.15%

County results
Tuttle:      40–50%      50–60%
Amsden:      40–50%      50–60%

Governor before election

David H. Goodell
Republican

Elected Governor

Hiram A. Tuttle
Republican

The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.

General election

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Candidates

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Major party candidates

  • Hiram A. Tuttle, Republican
  • Charles H. Amsden, Democratic

Other candidates

  • Josiah M. Fletcher, Prohibition

Results

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1890 New Hampshire gubernatorial election[1]
Party Candidate Votes % ±%
Republican Hiram A. Tuttle 42,479 49.26%
Democratic Charles H. Amsden 42,386 49.15%
Prohibition Josiah M. Fletcher 1,343 1.56%
Majority 93
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 16, 2020.