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1872 United States presidential election in New Hampshire

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1872 United States presidential election in New Hampshire

← 1868 November 5, 1872 1876 →
 
Nominee Ulysses S. Grant Horace Greeley
Party Republican Liberal Republican
Home state Illinois New York
Running mate Henry Wilson Benjamin G. Brown
Electoral vote 5 0
Popular vote 37,168 31,425
Percentage 53.94% 45.61%

County Results

President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

The 1872 United States presidential election in New Hampshire took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose five electors to the Electoral College, which selected the president and vice president.

New Hampshire was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri by a margin of 8.33%.

Horace Greeley had been born in New Hampshire. More specifically, in the town of Amherst.

Results

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1872 United States presidential election in New Hampshire[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Henry Wilson of Massachusetts 37,168 53.94% 5 100.00%
Liberal Republican Horace Greeley of New York Benjamin Gratz Brown of Missouri 31,425 45.61% 0 0.00%
Prohibition James Black of Pennsylvania John Russell of Michigan 200 0.29% 0 0.00%
Bourbon Democrat Charles O’Conor of New York John Quincy Adams II of Massachusetts 113 0.16% 0 0.00%
Total 68,906 100.00% 5 100.00%

See also

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References

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  1. ^ "1872 Presidential General Election Results - New Hampshire". Archived from the original on December 2, 2008.