1865 New Hampshire gubernatorial election
Appearance
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![]() County results Smyth: 50–60% 60–70% Harrington: 50–60% | |||||||||||||||||
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Elections in New Hampshire |
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The 1865 New Hampshire gubernatorial election was held on 14 March 1865 in order to elect the Governor of New Hampshire. Republican nominee and incumbent Mayor of Manchester Frederick Smyth defeated Democratic nominee and former Mayor of Manchester Edward W. Harrington.[1]
General election
On election day, 14 March 1865, Republican nominee Frederick Smyth won the election by a margin of 6,128 votes against his opponent Democratic nominee Edward W. Harrington, thereby retaining Republican control over the office of Governor. Smyth was sworn in as the 30th Governor of New Hampshire on 7 June 1865.[2]
Results
Party | Candidate | Votes | % | |
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Republican | Frederick Smyth | 34,145 | 54.91 | |
Democratic | Edward W. Harrington | 28,017 | 45.06 | |
Scattering | 18 | 0.03 | ||
Total votes | 52,180 | 100.00 | ||
Republican hold |
References
- ^ "Frederick Smyth". National Governors Association. Retrieved 3 April 2024.
- ^ "NH Governor". ourcampaigns.com. 8 February 2013. Retrieved 3 April 2024.
Categories:
- 1865 New Hampshire elections
- New Hampshire gubernatorial elections
- 1865 United States gubernatorial elections
- March 1865 events
- 1865 in New Hampshire
- 1860s in New Hampshire
- 1860s New Hampshire elections
- 1865 elections
- 1865 elections in North America
- 1865 elections in the United States
- United States gubernatorial elections in the 1860s
- Government of New Hampshire