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1998 ATP Tour World Championships – Doubles

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Doubles
1998 ATP Tour World Championships
Final
ChampionsNetherlands Jacco Eltingh
Netherlands Paul Haarhuis
Runners-upThe Bahamas Mark Knowles
Canada Daniel Nestor
Score6–4, 6–2, 7–5
Details
Draw8
Events
Singles Doubles
← 1997 · ATP Tour World Championships · 1999 →

Jacco Eltingh and Paul Haarhuis defeated Mark Knowles and Daniel Nestor in the final, 6–4, 6–2, 7–5 to win the doubles tennis title at the 1998 ATP Tour World Championships.[1]

Rick Leach and Jonathan Stark were the defending champions, but did not compete together in 1998. Stark failed to qualify with another partner; Leach partnered Ellis Ferreira, but was eliminated in the round-robin stage.

Seeds

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  1. Netherlands Jacco Eltingh / Netherlands Paul Haarhuis (champions)
  2. India Mahesh Bhupathi / India Leander Paes (round robin, withdrew due to a left ankle injury of Paes)
  3. Australia Todd Woodbridge / Australia Mark Woodforde (round robin)
  4. The Bahamas Mark Knowles / Canada Daniel Nestor (final)
  5. South Africa Ellis Ferreira / United States Rick Leach (round robin)
  6. Australia Sandon Stolle / Czech Republic Cyril Suk (round robin)
  7. France Olivier Delaître / France Fabrice Santoro (semifinals)
  8. United States Donald Johnson / United States Francisco Montana (semifinals)
  9. Australia Joshua Eagle / Australia Andrew Florent (round robin)

Draw

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Key

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Finals

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Semifinals Final
            
1 Netherlands Jacco Eltingh
Netherlands Paul Haarhuis
7 6  
8 United States Donald Johnson
United States Francisco Montana
61 4  
1 Netherlands Jacco Eltingh
Netherlands Paul Haarhuis
6 6 7    
4 The Bahamas Mark Knowles
Canada Daniel Nestor
4 2 5    
4 The Bahamas Mark Knowles
Canada Daniel Nestor
4 6 7
7 France Olivier Delaître
France Fabrice Santoro
6 4 5

Green group

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  Netherlands Eltingh
Netherlands Haarhuis
Australia Woodbridge
Australia Woodforde
South Africa Ferreira
United States Leach
France Delaître
France Santoro
RR
W–L
Set
W–L
Game
W–L
Standings
1 Netherlands Jacco Eltingh
Netherlands Paul Haarhuis
7–6(7–3), 6–4 6–4, 6–4 4–6, 7–5, 7–5 3–0 6–1 43–34 1
3 Australia Todd Woodbridge
Australia Mark Woodforde
6–7(3–7), 4–6 6–7(3–7), 3–6 7–6(7–1), 3–6, 4–6 0–3 1–6 33–44 4
5 South Africa Ellis Ferreira
United States Rick Leach
4–6, 4–6 7–6(7–3), 6–3 6–7(1–7), 6–4, 6–7(3–7) 1–2 3–4 39–39 3
7 France Olivier Delaître
France Fabrice Santoro
6–4, 5–7, 5–7 6–7(1–7), 6–3, 6–4 7–6(7–1), 4–6, 7–6(7–3) 2–1 5–4 52–50 2

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

Gold group

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  India Bhupathi
India Paes
Australia Eagle
Australia Florent
The Bahamas Knowles
Canada Nestor
Australia Stolle
Czech Republic Suk
United States Johnson
United States Montana
RR
W–L
Set
W–L
Game
W–L
Standings
2
9
India Mahesh Bhupathi
India Leander Paes
Australia Joshua Eagle
Australia Andrew Florent
7–6(7–5), 6–0
(w/ Eagle / Florent)
6–4, 3–6, 4–6
(w/ Bhupathi / Paes)
6–3, 4–6, 6–7(4–7)
(w/ Bhupathi / Paes)
0–2
1–0
2–4
2–0
29–32
13–6
5
4
4 The Bahamas Mark Knowles
Canada Daniel Nestor
6–7(5–7), 0–6
(w/ Eagle / Florent)
2–6, 6–4, 6–2 6–3, 6–2 2–1 4–3 32–30 1
6 Australia Sandon Stolle
Czech Republic Cyril Suk
4–6, 6–3, 6–4
(w/ Bhupathi / Paes)
6–2, 4–6, 2–6 7–6(8–6), 6–7(5–7), 6–7(4–7) 1–2 4–5 47–47 3
8 United States Donald Johnson
United States Francisco Montana
3–6, 6–4, 7–6(7–4)
(w/ Bhupathi / Paes)
3–6, 2–6 6–7(6–8), 7–6(7–5), 7–6(7–4) 2–1 4–4 41–47 2

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

References

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  1. ^ "1998 ATP Tour World Championships – Singles results". Association of Tennis Professionals (ATP).