1868 United States presidential election in Louisiana
Appearance
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Elections in Louisiana |
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The 1868 United States presidential election in Louisiana took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
Louisiana voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won the state by a margin of 41.38%.
With 70.69% of the popular vote, Louisiana would be Seymour's second strongest victory in terms of percentage in the popular vote after Kentucky.[1]
Results
[edit]1868 United States presidential election in Louisiana[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Horatio Seymour of New York | Francis Preston Blair, Jr. of Missouri | 80,225 | 70.69% | 7 | 100.00% | ||
Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 33,263 | 29.31% | 0 | 0.00% | ||
Total | 113,488 | 100.00% | 7 | 100.00% |
See also
[edit]References
[edit]- ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "1868 Presidential General Election Results - Louisiana".