1828 United States presidential election in Massachusetts
Appearance
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Turnout | 25.7%[1] ![]() | |||||||||||||||||||||||||
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![]() County Results
Adams 60-70% 80-90% 90-100%
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Elections in Massachusetts |
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The 1828 United States presidential election in Massachusetts took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
Massachusetts voted for the National Republican candidate, incumbent president John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Massachusetts by a landslide margin of 60.97%.
With 76.36% of the popular vote, Adams' home state would prove to be his second strongest victory in the 1828 election after neighboring Rhode Island.[2]
Results
[edit]1828 United States presidential election in Massachusetts[3] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
National Republican | John Quincy Adams (incumbent) | 29,836 | 76.36% | 15 | |
Democratic | Andrew Jackson | 6,012 | 15.39% | 0 | |
N/A | Other | 3,226 | 8.26% | 0 | |
Totals | 39,074 | 100.0% | 15 |
See also
[edit]References
[edit]- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "1828 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved February 28, 2013.