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1792 United States presidential election in Rhode Island

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1792 United States presidential election in Rhode Island

November 2 – December 5, 1792 1796 →
 
Nominee George Washington
Party Independent
Home state Virginia
Running mate George Clinton
Electoral vote 4
Percentage 100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Rhode Island took place as part of the 1792 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for President and Vice President.

Rhode Island unanimously voted for the incumbent Independent President George Washington.

Results

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1792 United States presidential election in Rhode Island[1]
Party Candidate Votes Percentage Electoral votes
Independent George Washington (incumbent) 4
Federalist John Adams 4
Totals 8

See also

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References

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  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved 2024-07-19.