1945 U.S. National Championships – Women's singles

Second-seeded Sarah Palfrey Cooke defeated first-seeded Pauline Betz 3–6, 8–6, 6–4 in the final to win the women's singles tennis title at the 1945 U.S. National Championships.[1]

Women's singles
1945 U.S. National Championships
Final
ChampionUnited States Sarah Palfrey Cooke[1]
Runner-upUnited States Pauline Betz
Score3–6, 8–6, 6–4
Details
Draw32
Seeds8
Events
Singles men women
Doubles men women
← 1944 · U.S. National Championships · 1946 →

Seeds

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The eight seeded U.S. players are listed below. Sarah Palfrey Cooke is the champion; others show in brackets the round in which they were eliminated.[2][3]

  1.   Pauline Betz (finalist)
  2.   Sarah Palfrey Cooke (champion)
  3.   Margaret Osborne (quarterfinals)
  4.   Louise Brough (semifinals)
  5.   Patricia Todd (quarterfinals)
  6.   Mary Arnold (quarterfinals)
  7.   Dorothy Bundy (quarterfinals)
  8.   Doris Hart (semifinals)

One foreign player was seeded.

  1.   Mary Terán de Weiss (second round)

Draw

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Final eight

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Quarterfinals Semifinals Finals
               
2   Sarah Palfrey Cooke 6 6
7   Dorothy Bundy 3 4
2   Sarah Palfrey Cooke 6 6
4   Louise Brough 3 4
4   Louise Brough 6 6
5   Patricia Todd 2 4
2   Sarah Palfrey Cooke 3 8 6
1   Pauline Betz 6 6 4
1   Pauline Betz 0 6 6
6   Mary Arnold 6 4 4
1   Pauline Betz 6 6
8   Doris Hart 3 2
3   Margaret Osborne 2 3
8   Doris Hart 6 6

References

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  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 470. ISBN 978-0942257700.
  2. ^ Official Tennis Guide 1946. [New York City]: A.S. Barnes and Company. 1946. pp. 37–39, 41.
  3. ^ "Parker, Betz Top Seeded". The Milwaukee Sentinel. AP. August 24, 1945. p. 5 (part 2).
Preceded by Grand Slam women's singles Succeeded by