The One-way Conjecture states that the existence of nonisomorphic NP-complete sets implies the existence of one-way functions.
Nov 15, 2020 · The type of argument you are looking for is as follows: If graph isomorphism were NP-complete, then some widely believed complexity assumption fails.
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Is graph non-isomorphism NP-complete?
Can two non-isomorphic graphs have the same degree sequence?
Is subgraph isomorphism NP-complete?
Is graph isomorphism P complete?
We will see in this lecture that Graph non - Isomorphism is in BP.NP (and in NP). Thus if Graph Isomorphism is NP complete then PH collapses.
It still could happen that PNP but that there exist NP complete sets which are not p-isomorphic. We conjecture that this is not the case. By the same ...
Theorem 1 If GI is NP-complete, then the polynomial hierarchy collapses (specifically, PH = Σ2). Proof. We first observe that AM ⊆ Π2 (why?). Now, assume GI is ...
As it is generally believed that NP-complete sets require exponential time, this is good evidence that Graph Isomorphism is in fact, NP-incomplete, but not in P ...
It was conjectured that all NP-complete sets are polynomially isomorphic, a statement which is known as the BermanHartmanis conjecture. Several consequences ...
The results on P-isomorphisms and constructing non-P-isomorphic sets apply also to sets complete for PTAPE, EXPTIME, and EXPTAPE and other classes. We also ...
Jan 3, 2015 · Firstly, Graph Isomorphism can not be NP-complete unless the polynomial hierarchy [1] collapses to the second level. Also, the counting[2] ...
We look at the problem of graph nonisomorphism. In this protocol, P is trying to convince. V that two graphs G0 and G1 are not isomorphic.
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