Aug 12, 2008 · Abstract:We prove that any k-uniform hypergraph on n vertices with minimum degree at least n/(2(k-1))+o(n) contains a loose Hamilton cycle.

In our proof of Theorem 1.1 we construct the loose Hamilton cycle by finding several paths and joining them into a spanning cycle.

We prove that any -uniform hypergraph on vertices with minimum degree at least contains a loose Hamilton cycle.

A cycle of order n is tight if every set of k consecutive vertices forms an edge; it is loose if every pair of adjacent edges intersects in a single vertex, ...

We say that a 3-uniform hypergraph has a Hamilton cycle if there is a cyclic ordering of its vertices such that every pair of consecutive vertices lies in a ...

We say that a k-uniform hypergraph (V,E) is a loose Hamilton cycle if there exists a cyclic ordering of the vertices V such that every edge consists of k ...

May 23, 2022 · A loose Hamilton cycle in a hypergraph is a cyclic sequence of edges covering all vertices in which only every two consecutive edges intersect and do so in ...

Mar 15, 2013 · A loose Hamilton cycle on n vertices is a set of edges e1,...,el such that for some cyclic order of the vertices every edge ei consists of k ...

A Hamilton `-cycle in an n-vertex, k-uniform hypergraph (1 ≤ ` < k) is an ordering of the ver- tices and an ordered subset of the edges such that each such edge ...

Feb 21, 2011 · A loose Hamilton cycle is a cycle of order n n in which every pair of adjacent edges intersects in a single vertex. We prove that if pnk−1/logn ...