Our proof of Theorem 1.1 implicitly shows that this problem is hard for c = 1 and some s = s(g) < 1, thus showing APX-hardness of. (1, g, 2g + 1)-Sat. We ...
People also ask
Is SAT a NP-hard problem?
Is 2sat NP-hard?
How to know if a problem is NP-hard?
How do we know if a SAT is NP-complete?
Abstract: We prove the following hardness result for anatural promise variant of the classical CNF-satisfiabilityproblem: Given a CNF-formula where each ...
We prove the following hardness result for a natural promise variant of the classical CNF-satisfiability problem: Given a CNF-formula where each clause has ...
1This is the sense in which we implied (2 + ε)-SAT is NP-hard in the paper title, but we should mention here that (2 + ε)-SAT has been used previously to ...
(2 + ε)-SAT is NP-hard. Per Austrin∗. Venkatesan Guruswami†. Johan Håstad‡. October 2013. Abstract. We prove the following hardness result for a natural promise ...
1This is the sense in which we implied (2 + ε)-SAT is NP-hard in the paper title, but we should mention here that. (2+ε)-SAT has been used previously to ...
Sep 28, 2017 · should mention here that (2 + ε)-SAT has been used previously to denote instances of satisfiability containing a mix of 2CNF and 3CNF clauses, ...
Nov 16, 2017 · In other words, a set system with discrepancy 1 is hard to distinguish from a set system with worst possible discrepancy. Finally, we prove a ...
We prove the following hardness result for a natural promise variant of the classical CNF-satisfiability problem: Given a CNF-formula where each clause has ...
In other words, a set system with discrepancy 1 is hard todistinguish from a set system with worst possible discrepancy. (2 + ε)-SAT is NP-hardPer Austrin ...
Missing: ε | Show results with:ε