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1864 United States presidential election in Indiana

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1864 United States presidential election in Indiana

← 1860 November 8, 1864 1868 →
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 13 0
Popular vote 150,422 130,233
Percentage 53.60% 46.40%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

The 1864 United States presidential election in Indiana took place on November 8, 1864, as part of the 1864 United States presidential election. Indiana voters chose 13 representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Indiana was won by the National Union candidate, incumbent Republican President Abraham Lincoln of Illinois and his running mate former Senator and Military Governor of Tennessee Andrew Johnson. They defeated the Democratic candidate, 4th Commanding General of the United States Army George B. McClellan of New Jersey and his running mate Representative George H. Pendleton of Ohio. Lincoln won the state by a margin of 7.2%.[1]

Results

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1864 United States presidential election in Indiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
National Union Abraham Lincoln of Illinois Andrew Johnson of Tennessee 150,422 53.60% 13 100.00%
Democratic George B. McClellan of New Jersey George H. Pendleton of Ohio 130,233 46.40% 0 0.00%
Total 280,655 100.00% 13 100.00%

See also

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References

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  1. ^ a b c "1864 Presidential Election Results Indiana".