Jacksonburg is a census-designated place (CDP) in Wetzel County, West Virginia, United States. It lies at an elevation of 748 feet (228 m).[3] As of the 2010 census, its population was 182.[2]
Jacksonburg | |
|---|---|
Census-designated place (CDP) | |
  Jacksonburg Location within the state of West Virginia | |
| Coordinates: 39°31′56″N 80°38′30″W / 39.53222°N 80.64167°W | |
| Country | United States |
| State | West Virginia |
| County | Wetzel |
| Area | |
| • Total | 1.501 sq mi (3.89 km2) |
| • Land | 1.481 sq mi (3.84 km2) |
| • Water | 0.020 sq mi (0.05 km2) |
| Population | |
| • Total | 182 |
| • Density | 120/sq mi (47/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
References
edit- ^ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. February 12, 2011. Retrieved April 23, 2011.
- ^ a b "U.S. Census website". United States Census Bureau. Retrieved May 14, 2011.
- ^ U.S. Geological Survey Geographic Names Information System: Jacksonburg, West Virginia
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